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Q: Find the least number which when divided by 8, 12 and 16, leaves 3 as the remainder in each case but when divided by 7 leaves no remainder
  • A. 266
  • B. 147
  • C. 149
  • D. 248
Correct Answer: Option B - Number = (LCM of 8, 12, and 16) k + 3 Number = 48k + 3 k = 3 putting = 48 × 3 + 3 144 + 3 = 147 Hence, number '147' is divisible by 7.
B. Number = (LCM of 8, 12, and 16) k + 3 Number = 48k + 3 k = 3 putting = 48 × 3 + 3 144 + 3 = 147 Hence, number '147' is divisible by 7.

Explanations:

Number = (LCM of 8, 12, and 16) k + 3 Number = 48k + 3 k = 3 putting = 48 × 3 + 3 144 + 3 = 147 Hence, number '147' is divisible by 7.