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Q: Barium loses………. electrons to achieve noble gas electronic configuration?
  • A. 1
  • B. 2
  • C. 3
  • D. 4
Correct Answer: Option B - The main property of any ideal gas is its stability. The stability of an element depends on the number of electrons present in its outer most shell. Elements which has eight electrons in its outer most shell is said to be stable element. Electronic configuration of Barium is 1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s² It is clear from this, by removing two electrons from its sixth shell (Because there will be eight electrons in the last orbit) it will achieve stability.
B. The main property of any ideal gas is its stability. The stability of an element depends on the number of electrons present in its outer most shell. Elements which has eight electrons in its outer most shell is said to be stable element. Electronic configuration of Barium is 1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s² It is clear from this, by removing two electrons from its sixth shell (Because there will be eight electrons in the last orbit) it will achieve stability.

Explanations:

The main property of any ideal gas is its stability. The stability of an element depends on the number of electrons present in its outer most shell. Elements which has eight electrons in its outer most shell is said to be stable element. Electronic configuration of Barium is 1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s² It is clear from this, by removing two electrons from its sixth shell (Because there will be eight electrons in the last orbit) it will achieve stability.