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Q: The least number which on being divided by 2, 3, 4, 5 and 6 leaves a remainder of 1 but no remainder when divided by 7 is :
  • A. 322
  • B. 301
  • C. 308
  • D. 315
Correct Answer: Option B - The smallest number = LCM of 2, 3, 4, 5 and 6 = 60, According to the question- , is divisible by 7. ∴Taking x = 5 Required number = 60 × 5 +1 = 301
B. The smallest number = LCM of 2, 3, 4, 5 and 6 = 60, According to the question- , is divisible by 7. ∴Taking x = 5 Required number = 60 × 5 +1 = 301

Explanations:

The smallest number = LCM of 2, 3, 4, 5 and 6 = 60, According to the question- , is divisible by 7. ∴Taking x = 5 Required number = 60 × 5 +1 = 301