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Q: Two adjacent sides of a rectangle are 3a² -6ab and 2a²+b². Its perimeter is:
  • A. 2a²+2b²–6ab
  • B. 10a²–12ab+2b²
  • C. 8a²+2b²–10ab
  • D. 5a²+b²–6ab
Correct Answer: Option B - आयत का परिमाप = 2 ( ल. + चौ.) = 2 (3a²-6ab + 2a² +b²) = 2 (5a² -6ab +b²) = 10a²- 12ab + 2b²
B. आयत का परिमाप = 2 ( ल. + चौ.) = 2 (3a²-6ab + 2a² +b²) = 2 (5a² -6ab +b²) = 10a²- 12ab + 2b²

Explanations:

आयत का परिमाप = 2 ( ल. + चौ.) = 2 (3a²-6ab + 2a² +b²) = 2 (5a² -6ab +b²) = 10a²- 12ab + 2b²