search
arrow-left Previous
Next arrow-right
Q: The average age of A, B and C is 20 years. Two years ago the sum of the ages of A and B was 6 more than the age of C. Find the present age of C.
  • A. 26 years
  • B. 29 years
  • C. 25 years
  • D. 28 years
Correct Answer: Option B - According to the question, Average age of A, B and C = 20 years Sum of total ages of A, B and C = 60 years 2 years ago- Sum of ages of (A + B + C) • 18 × 3 = 54 …….(i) Now, A + B = C + 6 ……..(ii) Putting the value of equation (ii) from equation (i) C + 6 + C = 54 2C = 48 2 years ago, age of C • 24 years Hence, the Present age of C • 24 + 2 = 26 years
B. According to the question, Average age of A, B and C = 20 years Sum of total ages of A, B and C = 60 years 2 years ago- Sum of ages of (A + B + C) • 18 × 3 = 54 …….(i) Now, A + B = C + 6 ……..(ii) Putting the value of equation (ii) from equation (i) C + 6 + C = 54 2C = 48 2 years ago, age of C • 24 years Hence, the Present age of C • 24 + 2 = 26 years

Explanations:

According to the question, Average age of A, B and C = 20 years Sum of total ages of A, B and C = 60 years 2 years ago- Sum of ages of (A + B + C) • 18 × 3 = 54 …….(i) Now, A + B = C + 6 ……..(ii) Putting the value of equation (ii) from equation (i) C + 6 + C = 54 2C = 48 2 years ago, age of C • 24 years Hence, the Present age of C • 24 + 2 = 26 years