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Q: N is a whole number which when, divided by 6 leaves the remainder 4. Find the remainder when 2N is divided by 6.
  • A. 4
  • B. 8
  • C. 2
  • D. Zero
Correct Answer: Option C - Let the quotient be “a” when N is divided by 6. ∴ N = 6a + 4……….(i) By equation (i) ×2, 2N = 2 × 6a + 8 2N = 12a + 6 + 2 2N = 6 (2a +1) + 2 Hence, the required remainder will be 2.
C. Let the quotient be “a” when N is divided by 6. ∴ N = 6a + 4……….(i) By equation (i) ×2, 2N = 2 × 6a + 8 2N = 12a + 6 + 2 2N = 6 (2a +1) + 2 Hence, the required remainder will be 2.

Explanations:

Let the quotient be “a” when N is divided by 6. ∴ N = 6a + 4……….(i) By equation (i) ×2, 2N = 2 × 6a + 8 2N = 12a + 6 + 2 2N = 6 (2a +1) + 2 Hence, the required remainder will be 2.