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Q: A natural number, when divided by 4, 5, 6 and 7, leaves a remainder of 3 in each case. What is the smallest of all such numbers?
  • A. 63
  • B. 423
  • C. 843
  • D. 213
Correct Answer: Option B - The required least number = (LCM of 4, 5, 6 and 7)+3 = 420+3 = 423
B. The required least number = (LCM of 4, 5, 6 and 7)+3 = 420+3 = 423

Explanations:

The required least number = (LCM of 4, 5, 6 and 7)+3 = 420+3 = 423