search
arrow-left Previous
Next arrow-right
Q: Which of the following numbers is divisible completely by both 9 and 11 ?
  • A. 277218
  • B. 10098
  • C. 12345
  • D. 181998
Correct Answer: Option B - Divisibility rule of 9 - When the sum of the digits of a number is divisible by 9 then the number is also divisible by 9. Divisibility rule of 11 - When the difference between the sum of the digit in even and odd place of a number is 0 (zero) or a multiple of 11, then the number will also be divisible by 11. From option (b), 1 + 0 + 0 + 9 + 8 = 18 i.e. 18 is divisible by 9 ∴ Option (d) us divisible by 9. And 10098 = (9 + 0) – (8+0+1) = 9–9 = 0 Hence option (b) 10098, is divisible by both 9 and 11.
B. Divisibility rule of 9 - When the sum of the digits of a number is divisible by 9 then the number is also divisible by 9. Divisibility rule of 11 - When the difference between the sum of the digit in even and odd place of a number is 0 (zero) or a multiple of 11, then the number will also be divisible by 11. From option (b), 1 + 0 + 0 + 9 + 8 = 18 i.e. 18 is divisible by 9 ∴ Option (d) us divisible by 9. And 10098 = (9 + 0) – (8+0+1) = 9–9 = 0 Hence option (b) 10098, is divisible by both 9 and 11.

Explanations:

Divisibility rule of 9 - When the sum of the digits of a number is divisible by 9 then the number is also divisible by 9. Divisibility rule of 11 - When the difference between the sum of the digit in even and odd place of a number is 0 (zero) or a multiple of 11, then the number will also be divisible by 11. From option (b), 1 + 0 + 0 + 9 + 8 = 18 i.e. 18 is divisible by 9 ∴ Option (d) us divisible by 9. And 10098 = (9 + 0) – (8+0+1) = 9–9 = 0 Hence option (b) 10098, is divisible by both 9 and 11.