search
arrow-left Previous
Next arrow-right
Q: What would be the highest value of X in the given equation. 5X1 + 6Y7 + 3Z3 = 1471
  • A. 5
  • B. 6
  • C. 7
  • D. 3
Correct Answer: Option B - Given 5X1 + 6Y7 + 3Z3 = 1471 For the highest value of X we will take the lowest value of Y and Z. So take Y = Z = 0 5X1 + 607 + 303 = 1471 5X1= 1471 – 910 = 561 Hence X = 6 So maximum possible value of X = 6
B. Given 5X1 + 6Y7 + 3Z3 = 1471 For the highest value of X we will take the lowest value of Y and Z. So take Y = Z = 0 5X1 + 607 + 303 = 1471 5X1= 1471 – 910 = 561 Hence X = 6 So maximum possible value of X = 6

Explanations:

Given 5X1 + 6Y7 + 3Z3 = 1471 For the highest value of X we will take the lowest value of Y and Z. So take Y = Z = 0 5X1 + 607 + 303 = 1471 5X1= 1471 – 910 = 561 Hence X = 6 So maximum possible value of X = 6