Correct Answer:
Option B - Given,
Power (P) = –5D
As we know that,
Power = 1/Focal Length(in metres)
Power = 100/Focal Length(in centimetres)
focal length (f) = 100/–5 = –20 cm
B. Given,
Power (P) = –5D
As we know that,
Power = 1/Focal Length(in metres)
Power = 100/Focal Length(in centimetres)
focal length (f) = 100/–5 = –20 cm