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Q: The average of the marks of three students in an examination to total 45 marks is 38. New two students appeared in the examination. What is the lowest marks that can be obtained by the new student who has scored less than the second new student, so that the total average of the marks of five students becomes 40?
  • A. 41
  • B. 42
  • C. 40
  • D. 43
Correct Answer: Option A - Sum of marks of all 5 students = 40 × 5 = 200 Sum of marks of first three students = 38 × 3 = 114 Sum of mark of remaining two new students = 200–114 = 86 Maximum marks in examination = 45 Hence, one of two new students can score a maximum 45 marks. and second student can get minimum (86 – 45) = 41 marks
A. Sum of marks of all 5 students = 40 × 5 = 200 Sum of marks of first three students = 38 × 3 = 114 Sum of mark of remaining two new students = 200–114 = 86 Maximum marks in examination = 45 Hence, one of two new students can score a maximum 45 marks. and second student can get minimum (86 – 45) = 41 marks

Explanations:

Sum of marks of all 5 students = 40 × 5 = 200 Sum of marks of first three students = 38 × 3 = 114 Sum of mark of remaining two new students = 200–114 = 86 Maximum marks in examination = 45 Hence, one of two new students can score a maximum 45 marks. and second student can get minimum (86 – 45) = 41 marks