Correct Answer:
Option A - Sum of marks of all 5 students = 40 × 5 = 200
Sum of marks of first three students = 38 × 3 = 114
Sum of mark of remaining two new students = 200–114 = 86
Maximum marks in examination = 45
Hence, one of two new students can score a maximum 45 marks.
and second student can get minimum (86 – 45) = 41 marks
A. Sum of marks of all 5 students = 40 × 5 = 200
Sum of marks of first three students = 38 × 3 = 114
Sum of mark of remaining two new students = 200–114 = 86
Maximum marks in examination = 45
Hence, one of two new students can score a maximum 45 marks.
and second student can get minimum (86 – 45) = 41 marks