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Q: The ages of father and son differ by 15 years. 5 years ago the father was twice as old as his son. Find the present age of both of them.
  • A. 40 years, 25 years
  • B. 35 years, 20 years
  • C. 30 years, 15 years
  • D. 45 years, 30 years
Correct Answer: Option B - The present age of son = x years then, the present age of father = (x + 15) years According to the question, (x + 15 – 5) = 2 × (x–5) x + 10 = 2x – 10 x = 20 Hence, Son's age = x = 20 years Father's age = x + 15 = 35 years
B. The present age of son = x years then, the present age of father = (x + 15) years According to the question, (x + 15 – 5) = 2 × (x–5) x + 10 = 2x – 10 x = 20 Hence, Son's age = x = 20 years Father's age = x + 15 = 35 years

Explanations:

The present age of son = x years then, the present age of father = (x + 15) years According to the question, (x + 15 – 5) = 2 × (x–5) x + 10 = 2x – 10 x = 20 Hence, Son's age = x = 20 years Father's age = x + 15 = 35 years