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Q: Following the National Building Code of India 2016. If W is the width of supported wall (in mm units), the width at the base of wall foundation (in mm units) B, shall NOT be less than.
  • A. B = W + 250
  • B. B = W + 100
  • C. B = W + 300
  • D. B = W + 200
Correct Answer: Option C - As per NBC 2016, width of footings shall be such that maximum stress in the concrete or masonry remains within the permissible limits. • The width of wall foundation shall not be less than that. B = W + 300 • The design of building foundations, the minimum depth of foundation for the load bearing wall is 300 mm. • As per IS 456 : 2000, thickness at the edge of footing- (i) When footing on soils, thickness = 150 mm (ii) When footing on piles, thickness = 300 mm
C. As per NBC 2016, width of footings shall be such that maximum stress in the concrete or masonry remains within the permissible limits. • The width of wall foundation shall not be less than that. B = W + 300 • The design of building foundations, the minimum depth of foundation for the load bearing wall is 300 mm. • As per IS 456 : 2000, thickness at the edge of footing- (i) When footing on soils, thickness = 150 mm (ii) When footing on piles, thickness = 300 mm

Explanations:

As per NBC 2016, width of footings shall be such that maximum stress in the concrete or masonry remains within the permissible limits. • The width of wall foundation shall not be less than that. B = W + 300 • The design of building foundations, the minimum depth of foundation for the load bearing wall is 300 mm. • As per IS 456 : 2000, thickness at the edge of footing- (i) When footing on soils, thickness = 150 mm (ii) When footing on piles, thickness = 300 mm