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Q: A porter lifts 500 N up to a distance of 100 meters work done by the porter is-
  • A. 50N
  • B. 0.20N
  • C. 0N
  • D. 5N
Correct Answer: Option C - A porter lifts 500N up to a distance of 100 meters then the work done by porter is zero because the displacement of the object is perpendicular to the direction of the force applied. So, the angle between the force and displacement is 90 degrees (θ = 90°). Work done = F.dcosθ = F.dcos90⁰ =0
C. A porter lifts 500N up to a distance of 100 meters then the work done by porter is zero because the displacement of the object is perpendicular to the direction of the force applied. So, the angle between the force and displacement is 90 degrees (θ = 90°). Work done = F.dcosθ = F.dcos90⁰ =0

Explanations:

A porter lifts 500N up to a distance of 100 meters then the work done by porter is zero because the displacement of the object is perpendicular to the direction of the force applied. So, the angle between the force and displacement is 90 degrees (θ = 90°). Work done = F.dcosθ = F.dcos90⁰ =0