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Q: A father is presently 3 times his daughter's age. After 10 years he will be twice as old as her. Find the daughter's present age.
  • A. 15 years
  • B. 5 years
  • C. 20 years
  • D. 10 years
Correct Answer: Option D - Let the present age of daughter = x years then the present age of father = 3x years According to the question, After 10 years, 2(x +10) = 3x + 10 2x + 20 = 3x + 10 x = 10 years
D. Let the present age of daughter = x years then the present age of father = 3x years According to the question, After 10 years, 2(x +10) = 3x + 10 2x + 20 = 3x + 10 x = 10 years

Explanations:

Let the present age of daughter = x years then the present age of father = 3x years According to the question, After 10 years, 2(x +10) = 3x + 10 2x + 20 = 3x + 10 x = 10 years