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Q: A double stranded DNA has 18% cytosin, the percentage of other basess will be एक द्विसूत्रीय डी॰ एन॰ ए॰ में18% साइटोसिन है तो दूसरे क्षारों का प्रतिशत होगा-
  • A. A -18%, T – 32%, G – 32%
  • B. A – 32%, T – 18%, G – 32%
  • C. A – 32%, T – 32%, G – 18 %
  • D. A – 18%, T – 32%, G – 32%
Correct Answer: Option C - A – 32%, T – 32%, G – 18 % A = Adenine, T = Thymin, G = Guanin, C = Cytosin A = T A + G = 50% (प्यूरीन) G = C T + C = 50% (पिरीमिडीन) C = 18% दिया है अत: G = C, lees G = 18% A + G = 50% T + C = 50% A + 18% = 50% T + 18 = 50% A = 32% T = 32%
C. A – 32%, T – 32%, G – 18 % A = Adenine, T = Thymin, G = Guanin, C = Cytosin A = T A + G = 50% (प्यूरीन) G = C T + C = 50% (पिरीमिडीन) C = 18% दिया है अत: G = C, lees G = 18% A + G = 50% T + C = 50% A + 18% = 50% T + 18 = 50% A = 32% T = 32%

Explanations:

A – 32%, T – 32%, G – 18 % A = Adenine, T = Thymin, G = Guanin, C = Cytosin A = T A + G = 50% (प्यूरीन) G = C T + C = 50% (पिरीमिडीन) C = 18% दिया है अत: G = C, lees G = 18% A + G = 50% T + C = 50% A + 18% = 50% T + 18 = 50% A = 32% T = 32%