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Q: A current of 0.8 A is drawn by a filament of on electric bulb for 3 minutes. Amount of electric change that flows through the circuit is . . . . . .
  • A. 1.44
  • B. 144
  • C. 14.4
  • D. 0.144
Correct Answer: Option B - Hence the formula Q = I.t , t = 3minuts =3x60=180 seconds I = 0.8A Where, I = Current, Q = electrical charge, t = time Q = 0.8 × 180 = 144 C
B. Hence the formula Q = I.t , t = 3minuts =3x60=180 seconds I = 0.8A Where, I = Current, Q = electrical charge, t = time Q = 0.8 × 180 = 144 C

Explanations:

Hence the formula Q = I.t , t = 3minuts =3x60=180 seconds I = 0.8A Where, I = Current, Q = electrical charge, t = time Q = 0.8 × 180 = 144 C