Question

A circle is inscribed in ∆ABC, touching AB, BC and AC at the points P, Q and R respectively. If AB – BC = 4 cm, AB – AC = 2 cm and the perimeter of ∆ABC = 32 cm, then PB + AR is equal to :

• A.
• B. 12 cm
• C. 13 cm
• D.

Answer 1

Answer: (A)